Even with Michigan and Florida Obama will lead
May 7, 2008 at 8:12 pm | In politics |Tags: Barack Obama, Florida, Hillary Clinton, Kentucky, Michigan, Montana, Oregon, Puerto Rico, South Dakota, Super Delegates, West Virginina
Once again the Clinton campaign says it’s not going to quit despite the fact that she can’t pass Obama. She’s saying count Florida and Michigan. This despite the fact that she agreed in 2007 that they shouldn’t count because they broke DNC rules.
But she and her supporters are going to whine until the cows come home so I decided to do some math.
What if Michigan and Florida count using the votes from their January primaries?
In Michigan let’s give Hillary her win. And let’s give all the uncommitted votes to Obama.
That gives Clinton 85 delegates and Obama 62 delegates
In Florida let’s give Hillary her win too.
That gives Clinton 105 delegates and Obama 69 delegates.
That givens Clinton 1,876 delegates and Obama 1,973
Then let’s move on to the remaining six contests. Let’s say it goes down this way.
Clinton wins West Virginia 69/31
Clinton wins Kentucky-66/34
Obama wins Oregon-56/44
Obama wins Montana-53/47
Obama wins South Dakota 56/44
Clinton wins Puerto Rico 60/40
If all that happens Clinton will have 1,998 delegates and Obama will have 2,068 delegates.
Clinton will still be behind.
If Florida and Michigan counts then the winning candidate needs to get to 2,209 delegates to get the nomination.
Clinton will need 77% of the superdelegates to get to 2,209
Obama will need 52% of the superdelegates to get to 2,209

Even with Michigan and Florida as is the math is still in Obama’s corner.
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